Ima li koja plemenita duša da mi kaze kako da ovo izjednačim:
2KMnO4+16HBr=5Br2+2KBr+2MnBr2+8H20
Mislim kak dobit koeficijente,da li moze preko oksidoredukcione seme?Hvala!
..+7.............-1........0.................+2 KMnO4 + HBr = Br2 + KBr + MnBr2 + H2O
+7.............+2 Mn +5e = Mn......../•2
-1...............0 Br – 1e = Br..../•5 /•2
2KMnO4 + 16HBr = 5Br2 + 2KBr + 2MnBr2 + 8H2O
Hvala,hvala!
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..+7.............-1........0.
..+7.............-1........0.................+2
KMnO4 + HBr = Br2 + KBr + MnBr2 + H2O
+7.............+2
Mn +5e = Mn......../•2
-1...............0
Br – 1e = Br..../•5 /•2
2KMnO4 + 16HBr = 5Br2 + 2KBr + 2MnBr2 + 8H2O
Hvala,hvala!
Hvala,hvala!