Koliko je cm3 vodonika i kiseonika (pri n.u.) potrebno za dobijanje 100cm3 H2O?
2H2O------------------>2H2+O2
1 mol--------------------22.4 dm3
x mol----------------------0.1 dm3
x=0.1*1/22.4=0.00446 mol H2O
n(O2)=n(H2O)/2=0.00446/2=0.00223 mol
V(O2)=n(O2)*22.4=0.00223*22.4=0.050 dm3=50 cm3
n(H2)=n(H2O)=0.00446 mol
V(H2)=n(H2)*22.4=0.00446*22.4=0.1 dm3=100 cm3
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Zadatak
2H2O------------------>2H2+O2
1 mol--------------------22.4 dm3
x mol----------------------0.1 dm3
x=0.1*1/22.4=0.00446 mol H2O
n(O2)=n(H2O)/2=0.00446/2=0.00223 mol
V(O2)=n(O2)*22.4=0.00223*22.4=0.050 dm3=50 cm3
n(H2)=n(H2O)=0.00446 mol
V(H2)=n(H2)*22.4=0.00446*22.4=0.1 dm3=100 cm3