Ugljovodonici

CH4+4Cl2------------------->CCl4+4HCl

1 mol-------------------22.4 dm3

x mol-----------------------1*10(3) dm3

x=1*10(3)*1/22.4=44.64 mol metana

n(CCl4):n(metana)=1:1

n(CCl4)=n(metana)=44.64 mol

m(CCl4)=n(CCl4)*Mr=154*44.64=6874.56 g

6874.56 g---------------------100%

x g-----------------------------------85%

x=6874.56*85/100=5843.38 g=5.84338 kg CCl4