Izracunati maseni udio Kalijuma u karnalitu KCl*MgCl2*6H2O?
karnalit KCl*MgCl2*6H2O
w(K)=Ar(K)/Mr=39/277.5=0.1405=14.05 %
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karnalit KCl*MgCl2*6H2O
w(K)=Ar(K)/Mr=39/277.5=0.1405=14.05 %