Pripremiti 200 g rastvora natrijum karbonata ako mu je molalitet 1,008 mol kg-1 RJEŠENJE: 19,31g
mr=m(rastvaraca)+ms
m(rastvaraca)=mr-ms
b=n/m(rastvaraca)
1.008=ms/Mr*(0.2-ms)
1.008*0.106*0.2-1.008*0.106*ms=ms
0.02137=ms+0.107
1.107*ms=0.02137
ms=0.02137/1.107=0.01931 kg=19.31 g
Mr=0.106 kg/mol a mr=0.2 kg sve mora da se pretvori u kg jer je molalitet u mol/kg
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Koncentracija
mr=m(rastvaraca)+ms
m(rastvaraca)=mr-ms
b=n/m(rastvaraca)
1.008=ms/Mr*(0.2-ms)
1.008*0.106*0.2-1.008*0.106*ms=ms
0.02137=ms+0.107
1.107*ms=0.02137
ms=0.02137/1.107=0.01931 kg=19.31 g
Mr=0.106 kg/mol a mr=0.2 kg sve mora da se pretvori u kg jer je molalitet u mol/kg