HITNO! ORGANSKA HEMIJA

(CxH2x+2)+(3*x/2+1/2)O2---------------->xCO2+(x+1)H2O

m(CxH2x+2):m(H2O)=Mr(CxH2x+2):(x+1)*Mr(H2O)

Mr(CxH2x+2)=x*Ar(C)+2*x*Ar(H)+2*Ar(H)

14.2:19.8=(12*x+2*x+2):18*(x+1)

19.8*(14*x+2)=18*(x+1)*14.2

277.2*x+39.6=255.6*x+255.6

277.2*x-255.6*x=255.6-39.6

21.6*x=216

x=216/21.6=10 i formula je C10H22

2C10H22+31*O2------------------>20CO2+22H2O

n(C10H22)=ms/Mr=14.2/142=0.1 mol

n(O2):n(C10H22)=31:2

n(O2)=n(C10H22)*31/2=0.1*31/2=1.55 mol

1 mol-------------------------22.4 dm3

1.55 mol----------------------x dm3

x=1.55*22.4/1=34.72 dm3

Hvala puno.