Izracunati maseni udeo kiseonika u dolomitu i H2O u di-hidritu gipsa.
Unapred zahvalan :)
w(O)=6*Ar(O)/Mr
dolomit CaMg(CO3)2
w(O)=6*16/184=0.5217=52.17 %
dihidrat gipsa a ne dihidrit CaSO4*2H2O
w(H2O)=2*Ar(H2O)/Mr=2*18/172=0.209=20.9 %
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Zadatak
w(O)=6*Ar(O)/Mr
dolomit CaMg(CO3)2
w(O)=6*16/184=0.5217=52.17 %
dihidrat gipsa a ne dihidrit CaSO4*2H2O
w(H2O)=2*Ar(H2O)/Mr=2*18/172=0.209=20.9 %