Koliko mL vode treba dodati u 20 mL 0,1 mol/L vodenog rastvora hlorovodonične kiseline da bi se dobio rastvor količinske koncentracije 0,025 mol/L?
n1(HCl)=c1*V1=0.02*0.1=0.002 mol
n1(HCl)=n2(HCl)=0.002 mol
V2=n2(HCl)/c2=0.002/0.025=0.08=80 ml
V(vode)=V2-V1=80-20=60 ml
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Rastvor
n1(HCl)=c1*V1=0.02*0.1=0.002 mol
n1(HCl)=n2(HCl)=0.002 mol
V2=n2(HCl)/c2=0.002/0.025=0.08=80 ml
V(vode)=V2-V1=80-20=60 ml