Koliko se primesa u % nalazi u HgO, ako se zagrevanjem njegovih 220 g oslobodi 11,2 L kiseonika, pri V0? Hg-200,6
2HgO------------->2Hg+ O2
m1(HgO)=220 g
1 mol-----------------22.4 dm3
x mol------------------11.2 dm3
x=11.2*1/22.4=0.5 mol O2
n(HgO):n(O2)=2:1
n(HgO)=2*n(O2)/1=2*0.5/1=1 mol
m(HgO)=n(HgO)*Mr=1*216.6=216.6 g
m(primesa)=m1(HgO)-m(HgO)=220-216.6=3.4 g
w(primesa)=m(primesa)/m1(HgO)=3.4/220=0.015=1.5 %
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Primese
2HgO------------->2Hg+ O2
m1(HgO)=220 g
1 mol-----------------22.4 dm3
x mol------------------11.2 dm3
x=11.2*1/22.4=0.5 mol O2
n(HgO):n(O2)=2:1
n(HgO)=2*n(O2)/1=2*0.5/1=1 mol
m(HgO)=n(HgO)*Mr=1*216.6=216.6 g
m(primesa)=m1(HgO)-m(HgO)=220-216.6=3.4 g
w(primesa)=m(primesa)/m1(HgO)=3.4/220=0.015=1.5 %